ME: Thermodynamics MCQs Previous Questions Answers

Basic mechanical Engineering Questions Answers Previous years Question papers Answers MCQs Online Exams for Free

mechanical Engineering MCQs Thermodynamics

Thermodynamics is the science of Energy, Entropy and Equilibrium. it can also be stated that Science that deals with heat and Work.
Why We are studying Thermodynamics : Thermodynamics finds applications in all power producing as well as power absorbing devices.
below are some Basic and Mostly asked question in Mechanical Engineering Sections for various Jobs and Competitive Exams. These questions are based on previous years questions asked in junior Engineer, GATE, various SSC, UPSC, PSC Exams. It also include the solution of the answers with more details regarding the answer.
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1.Heat and Work are ……..

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    •  Answer
      • Path functions
    • Solution
      • If a thermodynamic system passes through a series of states, it is said to follow a path. If the thermodynamic variables depends upon the path followed by the system it is said to be a path function. Here heat and work depends upon the path of the system. That means to reach state 2 from state 1 the amount of work done or Heat rejected/supplied depends upon the path. If M is a property Integral M =/ M2- M1 , then it is called path function. By knowing the end states we cannot find the change in the property Otherwise it is called state functions/Point function Eg: Pressure, temperature, Volume

2. Which of the following variables control the physical properties of gas
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
      • When pressure increases the volume of the gas increases, ie pressure changes make changes in the physical property. Same as in the case of temperature. Volume is always a physical quantity.
3. Which law is applicable for the behavior of perfect gas 
  • [accordion]
    •  Answer
      • Boyle’s law, Charles Law, Gay-Lussac Law
    • Solution
      • Boyle’s Law : PV= Constant at constant T Charle’s Law : P/T = Constant at Constant V Gay Lussac law :
4.The unit of temperature in SI unit is
  • [accordion]
    •  Answer
      • Kelvin (K)
    • Solution


5. The unit of mass in SI unit is
  • [accordion]
    •  Answer
      • Kilogram (Kg)
    • Solution

6. The unit of length in SI unit is
  • [accordion]
    •  Answer
      • Meter (m)
    • Solution

 7 The unit of energy in SI unit is
  • [accordion]
    •  Answer
      • Joule (J)
    • Solution

 8 According to gay-Lussac law for a perfect gas the absolute pressure of a given mass varies directly as
  • [accordion]
    •  Answer
      • Absolute temperature if volume is kept constant
    • Solution

 9 An ideal gas as compare to a real gas at very high temperature occupies (Volume)…. ?
  • [accordion]
    •  Answer
      • More volume Solution
    • Solution


 10 General gas equation is
  • [accordion]
    •  Answer
      • PV=mRT
    • Solution

[next]
 11 According to Dalton's law the total pressure of a mixture of gas is equal to
  • [accordion]
    •  Answer
      • Sum of Partial pressure of all
    • Solution

 12 The condition of perfect vacuum, ie absolute zero pressure can be attained at
  • [accordion]
    •  Answer
      • a temperature of -273.16 C
    • Solution

 13 Extensive property of a system is one whose value
  • [accordion]
    •  Answer
      • depends on the mass of the system, like volume
    • Solution

14 Work done in a free expansion process is
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
 Ans : zero Solution : Work Done W = P*(V2-V1) , but change in volume of the system is zero and W= 0 We also know Q=W+U and Q=W=U=0
 15 The statement that molecular weights to all gases occupy the same volume is known as
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
 Ans : Avogadro’s hypothesis
 16 To convert volumetric analysis to Gravimeter analysis the relative volume of each constituent of the flue gases is
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
 Ans : multiplied by its molecular weight
 17 if a gas is heated against a pressure, keeping the volume constant, then work done will be equal to
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
Ans : zero Solution : W= P*(V2-V1)
 18 An isolated system is one in which..
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    •  Answer
      • Neither mass nor energy crosses the boundaries of the system
    • Solution

 19 properties of substances like pressure, temperature and density in thermodynamic coordinates are
  • [accordion]
    •  Answer
      • point functions or State Functions
    • Solution

 20 Which of the following quantities is not the property of the system (Pressure, Temperature, Specific Volume , Heat, Density)
  • [accordion]
    •  Answer
      • Heat
    • Solution


[next]
 21 Which of the following can be regarded as gas so that gas laws could be applicable within the commonly encountered temperature limits
  • [accordion]
    •  Answer
      • O2 , N2, H2, Air
    • Solution

 22 intensive properties of a system is one whose value
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    •  Answer
      • Doesn't depend on the mass of the system like T& P
    • Solution

 23 According to Avogadro’s law for a given pressure and temperature each molecule of gas occupies
  • [accordion]
    •  Answer
      • Same volume
    • Solution

 24 Mixture of water and ice forms a
  • [accordion]
    •  Answer
      • heterogeneous system
    • Solution

 25 Heat and work are
  • [accordion]
    •  Answer
      • path functions
    • Solution

 26 Which of the following parameter is constant for a mole of gas at a given temperature and pressure
  • [accordion]
    •  Answer
      • Volume
    • Solution

 27 The value of n=1 in the polytropic process indicates
  • [accordion]
    •  Answer
      • it is isothermal process 28 Solids and liquids have
    • Solution

28. Missing
 Ans : One value of specific heat
 29 A perfect gas at 27 C is heated at constant pressure till its volume is doubled, the final temperature is
  • [accordion]
    •  Answer
      • 327 C
    • Solution

 30 Molecular volume of any perfect gas at 600x10~3 N/m2 and 27C will be
  • [accordion]
    •  Answer
      • 4.17 m3/kg mol
    • Solution

[next]
 31 Which of the following process are thermodynamically reversible
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    •  Answer
      •  Isothermal and Adiabatic process ( Not Constant pressure and Constant Volume Processes)
    • Solution

 32 A gas is compressed in a cylinder (incomplete question will update)
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    •  Answer

    • Solution

 33 for reversible adiabatic process change in entropy is
  • [accordion]
    •  Answer
      • Zero
    • Solution

34 Energy can neither be created nor be destroyed can be converted from one form to another
  • [accordion]
    •  Answer
      • First law of thermodynamics
    • Solution

 35 Change in enthalpy in a closed system is equal to the heat transferred if the process takes place at
  • [accordion]
    •  Answer
      • Constant Pressure
    • Solution

  36 According to first law of thermodynamics
  • [accordion]
    •  Answer
      • Total energy of the system remains constant
    • Solution

 37 The more effective way of increasing the efficiency of Carnot's engine is to
  • [accordion]
    •  Answer
      • decrease lower temperature
    • Solution

38 The latent heat of steam at pressure greater than atmospheric pressure in comparison to latent heat at atmospheric pressure is
  • [accordion]
    •  Answer
      • Less
    • Solution

39 An engine operates between temperature of 900 K and T2 , another engine between T2 and 400 k, for both to do equal work value of T2 will be
  • [accordion]
    •  Answer
      • 650 K
    • Solution

40 Addition of heat at constant pressure to a gas results in
  • [accordion]
    •  Answer
      • raising its temperature and doing external work
    • Solution

[next]
 41 If heat is exchanged in reversible manner, which of the following properties of the working substance will change accordingly
  • [accordion]
    •  Answer
      • Entropy
    • Solution

42 An actual engine is to be designed having same efficiency as the Carnot cycle, such a proportion is
  • [accordion]
    •  Answer
      • Possible, but lot of sophistication
    • Solution
      •  
43 For the thermodynamic process to be reversible the temperature difference between hot body and working substance should be
  • [accordion]
    •  Answer
      • Zero
    • Solution

 44 In a isothermal process, the internal energy
  • [accordion]
    •  Answer
      • Remains Constant
    • Solution

 45 Isochoric process is one in which
  • [accordion]
    •  Answer
      • no mechanical work is done by the system
    • Solution

46 Change in internal energy in a closed system is equal to heat transferred if the reversible process takes place at
  • [accordion]
    •  Answer
      • Constant Volume
    • Solution

 47 first law of TD
  • [accordion]
    •  Answer
      • Enables to determine change in internal energy of a system Doesn't help to predict whether the system will nor not undergo a change Doesn't enable to determine change in entropy
    • Solution

 48 in a Carnot cycle heat is transferred at
  • [accordion]
    •  Answer
      • constant temperature
    • Solution

 49 If a system after undergoing as series of process, returns to the initial state then
  • [accordion]
    •  Answer
      • Sum of heat and work transfer will be zero
    • Solution

  50 Entropy change depends upon
  • [accordion]
    •  Answer
      •  Heat transfer
    • Solution

[next]
 51 Minimum work in compressor is possible when the value of adiabatic index ‘n’ is equal to
  • [accordion]
    •  Answer
      • 1
    • Solution


 52 Which of the following is irreversible
  • [accordion]
    •  Answer
      • Throttling
    • Solution


 53 In order to a cycle to be reversible
  • [accordion]
    •  Answer
      • Pressure, temperature and Volume
    • Solution
      • Free expansion or friction resisted expansion/ compression process shouldn't be countered When heat is being absorbed, temperature of not source and working substance should be same When heat is being rejected temperature of cold source and working substance should be same
 54 According to first law of TD
  • [accordion]
    •  Answer
      • Heat and work are mutually convertible
    • Solution

 55 First law of TD furnishes relation between Heat, Work and properties of steam 56 Total heat of a substance is known as
  • [accordion]
    •  Answer
      • Enthalpy
    • Solution


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